球杆系统课程设计
1. 直角杆两端的小球杆做功
1.A:B=1:3 因为速度V=R*@ 角度用@表示
2.m*3r*sin(@-90) =2m*r*cos(@-90)
B球转过的角度@=90+arctan(2/3)
3.mv*v/2+2m*(v/3) (v/3)/2=mg*3r+2mg*r 就用连乘拉 见谅
B的速版率大小v=根号权下90gr/11
2. 请问这个传递函数的作用和原理,它是一个二阶滤波器吗
你可以讨论该传递函数对应的频率响应，即s在虚轴上的取值，s=jΩ
所以H(jΩ）=1/(1-0.005Ω^2+j0.135Ω),将Ω回值带入就可答以求出模值，而后就能看出是什么通了
omega=0:1000;
H=1./(1-0.005*omega.^2+j*0.135*omega);
plot(omega,abs(H))
3. 求助一道关于刚体定轴转动的题 (大学物理)
绕中心转动。
碰撞后质点的动量全部转移给球杆系统，系统质心以v/2匀速直线运动专。同时系统以角属动量J=mvl绕质心转动。
另一端怎么可能不动呢？如果饶它运动，他一定受到另一端的拉力，可是这个力没有和他平衡的！
张力T=m*w*w*(l/2),w为角速度。w=J/I。转动惯量I=2*m*(l/2)(l/2).
代入可得：T=2mv*v/l,指向质心。
冲量=入射质点动量=mv
4. 球杆系统（ball and beam system）（400字翻译）
Ball-beam system for automatic control, machinery and electronics, electrical engineering and so on the basis of professional courses designed to control the teaching experiment equipment, because the ball-beam system with the characteristics of open-loop instability, the need to design the controller to control the location of the ball, and its structure is simple and intuitive to understand. To meet the principle of automatic control, modern control engineering courses, such as the experimental requirements, but also can be used as motor learning, motor and drag, pattern recognition, such as laboratory equipment courses.
Ball-beam system is divided into the mechanical parts and control part of the two major components. Mechanical parts is a typical four-bar linkage, with a scale bar from the stainless steel rod and a linear displacement sensor that can pivot around its left rotation, the point of view through the control bar, you can control the ball in the location bar. Mechanical parts of DC servo motor-driven, by controlling the motor shaft angle, you can achieve the control point of view of the bar. Intelligent control of parts of IPM100 servo motion controller, IPM100 is based on the latest DSP controller technology, 36V, 3A all-digital intelligent servo drive unit can control the DC brushless, brush, or permanent magnet synchronous AC motor. The location of the ball through the linear displacement sensor acquisition, controller position error calculated in accordance with the volume control to control the motor shaft angle, the angle of the control bar so that the stability ball to the target location.
5. 刚体碰撞，刚体无弹性，碰撞后如何运动
碰撞后质点的动量全部转移给球杆系统，系统质心以v/2匀速直线运动。同时系统如果是完全弹性碰撞，那么运动质点施与刚体的冲量就等于它原来的冲量MV。非
6. 腾讯桌球金币获取方法一览 详解怎么玩
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